In order to find the energy of a photon, you need to know its **frequency** and its **wavelength**. The energy of a photon is given by the following equation:

E = hf

Where **h** is Planck’s constant and **f** is the frequency of the photon.

## How to find energy of photon

The energy of a photon can be calculated in two ways: If the photon’s frequency is known, we can use the formula **E = h f**. Max Planck proposed this equation, which is why it is known as Planck’s equation. If the photon’s wavelength is known, the photon’s energy can be calculated using the formula **E = h c λ**.

Similarly to how we can calculate the energy of a particle at rest, we can use E = mc^{2}. **In special relativity, it is shown that the kinetic energy of a moving object is:**

- E
_{k}= mc^{2}(γ – 1) - where γ = 1 / (1 – v
^{2}/c^{2})^{1/2} - and v is the velocity of the object.

**Now, let’s plug in some numbers. For simplicity, let’s assume our original particle has a mass of 1 kg, a speed of 5 m/s, and a wavelength of 5 cm. We can input these values into our equation and solve for E:**

E = (1)(3 x 10^{8})^{2}(1 / (1 – (5/3 x 10^{8})^{2})^{0.5}) – 1)

= 8.1 x 10^{16} J

**The energy associated with a single photon is given by E = h ν**, where E is the energy (SI units of J), h is Planck’s constant (h = 6.626 x 10–34 J s), and ν is the frequency of the radiation (SI units of s–1 or Hertz, Hz) (see figure below).

The value of Planck’s constant means that a photon always has the same energy, no matter what its frequency is. The energy of a photon is related to its frequency by the equation:

E = hν

Where E is the energy of the photon, h is Planck’s constant, and ν is the frequency of the radiation.

To find the energy of a photon when given its frequency, you would plug in the values for E and ν into the equation above and solve for h. Once you have h, you can then plug in the value for h into the equation to find the energy of the photon.

## How do you calculate eV energy of a photon?

The **energy** of a photon is usually given in electron volts (eV). To calculate the energy of a photon, we use the equation:

E = hf

where **E** is the energy of the photon, **h** is Planck’s constant, and **f** is the frequency of the photon.

Using this equation, we can calculate the energy of a 1 eV photon. First, we need to convert 1 eV to joules. 1 eV = 1.6 x 10^-19 coulombs x 1 volt = 1.6 x 10^-19 joules. Now we can calculate the frequency of the 1 eV photon. E = hf, so f = E/h. Hence, f = 1 eV/6.63 x 10-34 joule-sec x (1.6 x 10-19 joule / 1 eV) = 2.41 x 1014 sec-1 or 2.41 x 1014 Hz (Hz means 1/sec).

## What is the energy of one photon?

The energy of a single photon is: **hν or = (h/2π)ω where h is Planck’s constant: 6.626 x 10-34 Joule-sec**. One photon of visible light contains about 10-19 Joules (not much!) the number of photons per second in a beam.

In order to understand what the energy of one photon means, it is important to understand what a photon is. A photon is the fundamental particle of light. It is also the carrier of the electromagnetic force, which is the force that carries light and other electromagnetic radiation.

The energy of a photon is **directly related to its frequency**. The higher the frequency, the more energy the photon has. Conversely, the lower the frequency, the less energy the photon has.

**visible light** has a relatively low frequency when compared to other types of electromagnetic radiation, such as X-rays and gamma rays. This means that visible light photons have relatively low energies.

The energy of a single photon is **extremely small**, but when photons are emitted in large numbers, they can have a significant impact. For example, when sunlight hits your skin, it is made up of billions of photons.

While the individual energy of each photon is small, When multiplied by the number of photons in a beam of light, the total energy can be quite large.

## What is the energy of a photon of wavelength 12400?

Solution : Using Planck’s formula, we have **E=hf=(hc)/(lamda)** where **h=6.63xx10^(-34)J**s **c=3xx10^(8)ms^(-1)** **lamda=12400xx10^(10)m**

**E=((6.63xx10^(-34))(3xx10^(8)))/(12400xx10^(-10))=1eV**

Note, In general, **a photon of wavelength lamda(“in” A) will energy E(In eV) as given by E=(12400)/(lamda)**

## What is the formula of photon?

The energy of a photon can be calculated in two ways: If the photon’s frequency is known, we can use the formula E = h f . Max Planck proposed this equation, which is why it is known as Planck’s equation. If the photon’s wavelength is known, the photon’s energy can be calculated using the formula E = h c λ .

The frequency of a photon is related to its energy by **Planck’s constant**: E = hf. The higher the frequency of the photon, the higher its energy. A photon with a frequency of 5 × 10^{14} Hz has an energy of 2.4 eV.

The wavelength of a photon is inversely related to its energy by the **speed of light**: λ = c/E. The lower the energy of the photon, the longer its wavelength. A photon with a wavelength of 500 nm has an energy of 2.4 eV.

**What is the formula of photon?**

The answer is: E = hf = hc/λ.